Answer:
<u>a) divisible by 5: 120 numbers</u>
<u>b) divisible by 6: 360 numbers</u>
<u>c) divisible by 12: 192 numbers</u>
<u>d) divisible by 25: 24 numbers</u>
Step-by-step explanation:
6-digit numbers => the numbers have the form abcdef
a.) <u>divisible by 5</u>
f = {5}
a <u>5 values</u>; b <u>4 values</u>, c <u>3 values</u>, d <u>2 values</u> , e <u>1 value</u><em>, </em>f <em> </em><u>1 value</u>
=> 5 * 4 * 3 * 2 * 1 * 1 =<u> 120 numbers</u>
b.)<u> divisible by 6</u>
f = {2; 4; 6}
a <u>5 values</u>; b <u>4 values</u>, c <u>3 values</u>, d <u>2 values</u>, e <u>1 value</u>, f <u>3 values</u>
=> 5 * 4 * 3 * 2 * 1 * 3 = <u>360 numbers</u>
c.)<u> divisible by 12</u>
<u>ef</u> = {12; 16; 24; 32; 36; 52; 56; 64}
a <u>4 values</u>; b <u>3 values</u>, c <u>2 values</u>, d <u>1 value</u>, <u>ef</u> <u>8 values</u>
=> 4 * 3 * 2 * 1 * 8 =<u>192 numbers</u>
d.)<u> divisible by 25</u>
<u>ef</u> = {25}
a <u>4 values</u>; b 3<u> values</u>, c <u>2 values</u>, d 1 values, <u>ef</u> <u>1 value</u>
=> 4 * 3 * 2 *1*1 = <u>24 numbers</u>