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2 years ago

Which form of radiation is used to directly INCREASE the temperature of water in a nuclear reactor?

Physics

2 answers:

KengaRu [80]2 years ago

7 0

The correct answer to the question is : Gamma radiation.

EXPLANATION:

In a nuclear reactor, the water is heated due to the radiations coming from nuclear fission.

In the radioactive decay of uranium or other radio active substances, three types of radiations are produced which are known as alpha particle, beta particle and gamma ray.

Alpha particle is the double charged helium nucleus while beta is the stream of electrons. Hence, alpha and beta are the material particles. They are not radiations.

The gamma ray is an electromagnetic radiation. Hence, this will be responsible for heating water.

Hence, the correct answer is gamma radiations.

LuckyWell [14K]2 years ago

6 0

The answer would be D because is the strongest form of radiation

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the density of dry air at 20 degrees celsius is 1.20 g/L. What is the mass of air, in kilograms, of a room that measures 24.0m b

horsena [70]

<h2>Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.</h2>

Explanation:

Density of air = 1.20 g/L = $\frac{1.20\times 10^{-3}kg}{10^{-3}m^3}=1.2kg/m^3$

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2 years ago

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You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through

Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

$V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA$

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

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