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2 years ago

Write the linear equation is slope intercept form 5x-y=1/4

Mathematics

1 answer:

Lana71 [14]2 years ago

3 0

Slope intercept form of a line is y=mx+b where m= slope and b=y-intercept.

So, we need to convert the given equation in this form. For that simply solve the equation for y.

$5x-y=\frac{1}{4}$

$-y=-5x+\frac{1}{4}$ Subtract 5x from each sides.

$y=5x-\frac{1}{4}$ Multiply each sides by -1.

So, slope intercept frm is $y=5x-\frac{1}{4}$

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Which is the value of this expression when m=3 and n=-5? (6m^-1 n^0)^-3

iragen [17]

Answer:

The answer is C.

Step-by-step explanation:

I would simplify the expression first.

Equation: (6m^-1)^-3

You can get rid of n^0 because that equals 1.

Any expression raised to the power of -1 equals its reciprocal.

Equation: (6/m)^-3

Equation: (m/6)^3

Final Equation: m^3/216

Now, plug in 3.

(3)^3/216.

27/216 = 1/8

Hope this helps!

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2 years ago

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padilas [110]

Answer:

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Step-by-step explanation:

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2 years ago

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Arisa [49]

Answer:

X= 7

Step-by-step explanation:

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2 years ago

2x-y=10 y=-4x+2 substitution method

AlladinOne [14]

Answer:

the solution is (2, -6)

Step-by-step explanation:

Substitute the second equation into the first, replacing y in the first:

2x - (-4x+2) = 10

Simplifying, we get:

2x + 4x - 2 = 10, or:

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2 years ago

Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

bearhunter [10]

Answer:

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

6 0

2 years ago