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2 years ago

11

Pls help with sum geometry

2 answers:

erica [24]2 years ago

7 0

Answer:

$\Large \boxed{\mathrm{D}}$

Step-by-step explanation:

The triangles can be proven by AA or Angle-Angle similarity.

$\angle QUR \cong \angle TUS$

The vertical angles are congruent.

$\angle R \cong \angle S$

The alternate interior angles are congruent.

kaheart [24]2 years ago

4 0

YES! quite easily.

I hope you can see the two pairs of corresponding angles between the parallel lines. they'll be equal

and then there's a pair of vertically opposite angle at centre.

that means all pairs of corresponding angles are equal, thus, triangles are similar by AAA

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2 years ago

A motorboat covers the distance from one pier to the other pier in 4 hours and the way back in 5 hours. What is the speed of the

aleksklad [387]

R = speed in still water
r + c = speed with current
r - c = speed against current

3.5(r + c) = 70
r + c = 20
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2 years ago

What is 10 times 10 times 5?

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2 years ago

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Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

choli [55]

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(4-0)^2+(1-4)^2}$

$AB=\sqrt{(4)^2+(-3)^2}$

$AB=\sqrt{16+9}$

$AB=\sqrt{25}$

$AB=5$

Similarly,

$BC=\sqrt{(1-4)^2+(-3-1)^2}$

$BC=5$

$CD=\sqrt{(-3-1)^2+(0-(-3))^2}$

$CD=5$

And,

$AD=\sqrt{(-3-0)^2+(0-4)^2}$

$AD=5$

Now, the perimeter of the quadrilateral ABCD is:

$P=AB+BC+CD+AD$

$P=5+5+5+5$

$P=20$

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

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2 years ago