F=ma
a=(v2-v1)/(t2-t1)
a=(6-0)/(12-0)
a=6/12
a= .5 m/s^2
f=2300kg*.5m/s^2
f=1150N
f=1200N if using correct sig figs
Answer:
Explanation:
Let say the empty wagon has mass "M"
now by newton's II Law we will have
now it is given that empty wagon is pulled with acceleration 1.4 m/s/s
now we will have
now a child of mass three times the mass of wagon is sitting on the empty wagon
so here we have
so we have
Answer:
The curl is
Explanation:
Given the vector function
We can calculate the curl using the definition
Thus for the exercise we will have
So we will get
Working with the partial derivatives we get the curl