Answer:
5/24
Step-by-step explanation:
hope it works for u good luck
There would have to be one non club member, and 2 club members who bought the tickets.
To find the z-score for a weight of 196 oz., use
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
Answer:
there are 2 numbers between 1 and 4
Step-by-step explanation:
Answer:
i got 275.664
Step-by-step explanation: