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2 years ago

Find the first,fourth,and tenth terms of the arithmetic sequence described by the given rule. A(n) = 12+(n-1)(3)

1 answer:

4 0

The answers are:
the first term: 21
the fourth term: 22
the tenth term: 39

A(n) = 12+(n - 1)(3)

n = 1
A(1) = 12 + (1 - 1)(3) = 12 + 0*3 = 12 + 0 = 12

n = 4
A(4) = 12 + (4 - 1)(3) = 12 + 3*3 = 12 + 9 = 21

n = 10
A(10) = 12 + (10 - 1)(3) = 12 + 9*3 = 12 + 27 = 39

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I need help!! On this question please hurry

hichkok12 [17]

Step-by-step explanation:

Given:

Central Enlargement.

AC=4

AB=5

BC=3

Opp=3

Hyp=5

Required:

Sin<A

Formula:

Sin<A=Opp/hyp

Solution:

Sin<A=Opp/Hyp

Sin<A=3/5 or 0.6

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2 years ago

1 ) Find the volume of a cylinder with diameter 22 in and height 15 in.

OverLord2011 [107]

1. The volume of the cylinder is calculated through the equation, V = πr²h. Substituting the known values,
V = π(22 in/2)²(15 in) = 1815π in³ = 5701.99 in²
2. The answer to this item is letter "C. area of the base x height".
3. The volume of the prism is 5 x 5 x 10 cm or equal to 250 cm³.

6 0

3 years ago

Read 2 more answers

George earns 9% commission on all of his sales. He had sales of 89,400 for the month. Paris works for a different company, and a

Sholpan [36]

Answer: 10.53%

Step-by-step explanation:

George £89400 @ 9% = £8046 so income = £89400+£8046=£97446

Harris (Paris?) gets £447 more so 97446+447=£97893

and this represents sales of £89400 plus commission

so Harris' commission = £97893-£89400 = £8493

So last stage is what commission percentage is £8493 of original sales £89400 = 10.53%

8 0

2 years ago

How long is the base of a parallelogram if it has an area of 100 m2 and a height of 5 m?

DochEvi [55]

$\displaystyle\\
\bold{A= b \times h} \\ \\ 
\bold {\Longrightarrow~~~ b = \frac{A}{h} = \frac{100}{5} =}~ \boxed{\bold{20~m }}$

4 0

2 years ago

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

2 years ago