Which equation defines the graph of y=x^2 after it is shifted vertically 3 units down and horizontally 5 units left? A) y=(x-5)^ 2 - 3 B) y= (x+5)^2 - 3 c) y=(x-3)^2 - 5 D) y= (x+3)^2 - 5
2 answers:
we have
This is a vertical parabola open upward
the vertex is equal to the origin
The rule of the translation is
that means
the translations is units to the left and units down
therefore
the new vertex of the function will be
The new equation of the parabola in vertex form is equal to
<u>the answer is the option B</u>
The answers is B because you set x+5=0 and x=-5 so that means that the graph needs to be shifted 5 units to the left because 5 is negative and to move 3 units down you just put a -3 at the end of the equation like this y=(x+5)-3
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