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3 years ago

Which one is correct

Chemistry

2 answers:

Elodia [21]3 years ago

6 0

The answer is C because wind turbines spin creating electrical energy from mechanical energy

Ksju [112]3 years ago

3 0

The answer is C, because wind turbines are used to produce electricity, and it's also the most safest way--but they are expensive.

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What scientists do that is the basis for their investigation?

navik [9.2K]

Create a hypothesis, design an experiment the list varies really

4 0

3 years ago

Hydrazine (N₂H₄), a rocket fuel, reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the e

Vinvika [58]

At STP one mol weighs 22.4L

Moles of O_2

4.2/22.4
2.1/11.2
0.19mol

1 mol.O_2 can create 2mol water

moles of water

2(0.19)
0.38mol

Volume of water

0.38(22.4)
8.512L

8 0

1 year ago

Read 2 more answers

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

4 0

2 years ago

How does a sample of hydrogen at 10 °C compare to a sample of hydrogen at 350 K?

Andrej [43]

Answer: -

C. The hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Explanation: -

The kinetic energy of gas molecules increase with the increase in the temperature of the gas. With the increase in kinetic energy, the gas molecules also move faster. Thus with the increase of temperature, the speed of the molecules increase.

Temperature of first hydrogen gas sample is 10 °C.

10 °C means 273+10 = 283 K

Thus first sample temperature = 283 K

The second sample temperature of the hydrogen gas is 350 K.

Thus the temperature is increased.

So both the kinetic energy and speed of molecules is more for the hydrogen gas sample at 350 K.

Thus the hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Hence the answer is C.

7 0

2 years ago

Read 2 more answers

Draw the Lewis structure for sulfur tetrafluoride, SF4

Vlad [161]

Notes:-

S has Z=16

Electronic configuration

1s²2s²2p⁶3s²3p⁴

Valency is 4 and 6

Three fluorine atoms take 3 electrons and one lone pair present over S
As one electron remains unshared so we use + sign .

6 0

1 year ago