Classical conditioning requires _____.
2 answers:
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Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by
For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.
The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
The given parameters:
- <em>Throat area of the nozzle, </em>
<em> = 10 cm² = 0.001 m²</em>
- <em>The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²</em>
- <em>Air pressure at sea level = 101.325 kPa</em>
The ratio of the areas of the converging-diverging nozzle is calculated as follows;
From supersonic isentropic table, at , we can determine the following;
The tank pressure is calculated as follows;
Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
Learn more about converging-diverging nozzle design here: brainly.com/question/13889483