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3 years ago

8

11.

1 answer:

Mrrafil [7]3 years ago

8 0

Answer:

2 should be distributed as 2y + 16; y = 8

Step-by-step explanation:

We have to distribute 2, then:

Now we have to sum (-2y) in both sides of the equation:

Finally we have to divide both sides of the equation in 2:

Then the answer is 2 should be distributed as 2y + 16; y = 8

Hope this helps.

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

2 years ago

Danes puppy weighd 8oz at birth .The pup weighs 18 times more. So what is his weight now.

katrin [286]

You multiply 18 by 8 and you get 144
so the puppys weight is 144oz now

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2 years ago

Half of a sphere is stacked on top of a cone. They both share a circular base. The radius of the circle is 6 millimeters. The he

Flauer [41]

Answer:

312π mm^2

Step-by-step explanation:

to find the volume of the figure, you have to calculate the volume of a cone and the volume of a sphere divided it by 2.

The volume of a cone is 1/3 * π * r ^ 2 * h, replacing the information:

V = 1/3 * (6) ^ 2 * (14) = 168π mm^2

The volume of a sphere is 4/3 * π * r ^ 3, replacing the information:

V = 4/3 * π * (6) ^ 3 = 288π mm^2

but since you only have half the sphere

V = 288π / 2 = 144π mm^2

then the total volume is

Vt = 168π + 144π = 312π mm^2

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2 years ago

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What else would need to be congruent to show that ABC= DEF by ASA?

babunello [35]

Answer:

Option A

then you would have an angle, a side and another angle (ASA) next to each other

Opt.B would be a second sude (SAS)

Opt.C is already given

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2 years ago

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vlabodo [156]

Step-by-step explanation:

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2 years ago

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