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2 years ago

Really need help!!! quadratic equations UGH

2 answers:

5 0

2m³ + 10 m = 48

2m² + 10m - 48 = 0, solve this quadratic for m. Apply the formula:

m'=[-b + √(b²+4ac)]/2a and m" ==[-b - √(b²+4ac)]/2a

WHERE a = 2, b=10, c= - 48
and you will find :
m= 3 and m= - 8 (answer a)

kati45 [8]2 years ago

4 0

$2m^2 + 10m = 48\\
2m^2+10m-48=0\\
m^2+5m-24=0\\
m^2-3m+8m-24=0\\
m(m-3)+8(m-3)=0\\(m+8)(m-3)=0\\
m=-8 \vee m=3$

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5
−
8
x
|
|
5
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8
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|
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7
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x
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|
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|
=
±
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±
15
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x
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±
15
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5
-
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x
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x
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4
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<
5
2
x
<
5
2
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x
>
−
5
4
x
>
-
5
4
and
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<
5
2
x
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5
2
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