4
x
+
y
−
2
z
=
0
4
x
+
y
-
2
z
=
0
,
2
x
−
3
y
+
3
z
=
9
2
x
-
3
y
+
3
z
=
9
,
−
6
x
−
2
y
+
z
=
0
-
6
x
-
2
y
+
z
=
0
x
+
2
y
=
4
x
+
2
y
=
4
,
2
x
+
4
y
=
8
2
x
+
4
y
=
8
3
x
+
y
=
4
3
x
+
y
=
4
,
6
x
−
7
y
=
2
Answer:
Correct option: B
Step-by-step explanation:
The professor can perform a One-mean <em>t</em>-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.
A <em>t</em>-test will be used instead of the <em>z</em>-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.
The hypothesis for this test can be defined as follows:
<em>H₀</em>: The average score of the students in his class is not more then the entire university, i.e. <em>μ ≤ 35</em>.
<em>Hₐ</em>: The average score of the students in his class is more then the entire university, i.e. <em>μ > 35</em>.
Given:
The test statistic is:
Thus, the correct option is (B).
Answer:
Therefore , A=184
Step-by-step explanation:
Given function is
where T(t) is the temperature in °C and t is time in minute and A and k are constants.
She noticed that after 18 minutes the temperature of the pie is 138°C
Putting T(t) =138°C and t= 18 minutes
.....(1)
Again after 36 minutes it is 184°C
Putting T(t) =184°C and t= 36 minutes
.......(2)
Dividing (2) by (1)
Taking ln both sides
Putting the value k in equation (1)
⇒A= 184.
Therefore , A=184
Answer:
I know right?
Step-by-step explanation: