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2 years ago

10

A florist has an order to make flower bouquets. The order calls for the use of 45 roses and 63 carnations. Each bouquet made wil

l need to be the same.
If all of the flowers are to be used, there can be at most

bouquets made from the flowers requested in the order.

1 answer:

LUCKY_DIMON [66]2 years ago

4 0

The most bouquets possibke would be 9 because 45÷9=9 and 63÷7=9

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If x^2y^3=10 and x^3y^2=8, what is the value of x^5y^5

arlik [135]

Answer:

80.

Step-by-step explanation:

x^2y^3 * x^3y^2

= x^(2+3)y^(3+2)

= x^5y^5 and as x^2y^3 = 10 and x^3y^2 = 8 we have:

10 * 8

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2 years ago

If f(x) = 7+ 4x and g(x) = 1/2,

olchik [2.2K]

270

<h3>Further explanation</h3>

<u>Given:</u>

$\boxed{ \ f(x) = 7 + 4x \ }$
$\boxed{ \ g(x) = \frac{1}{2x} \ }$

<u>Question:</u>

What is the value of $\boxed{ \ \bigg( \frac{f}{g} \bigg)(5)? \ }$

<u>The Process:</u>

The form of $\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ }$ means that f(x) is divided by g(x).

$\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ } \rightarrow \boxed{ \ \frac{f(x)}{g(x)} \ }}$

Let us solve the problem.

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = \frac{7 + 4x}{\frac{1}{2x}} \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = (7 + 4x) \times \frac{2x}{1} \ }$

Thus, we get $\boxed{{ \ \bigg( \frac{f}{g} \bigg)(x) = 14x + 8x^2 \ }}$

And now, we can calculate the value of $\bigg( \frac{f}{g} \bigg)(5)$ .

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 14(5) + 8(5)^2 \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 70 + 200 \ }$

Thus, the value is 270.

- - - - - - - - - - -

Alternative thinking

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = \frac{7 + 4(5)}{\frac{1}{2(5)}} \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = (7 + 20) \times 10} \ }$

$\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 270 \ }}$

<h3>Learn more</h3>

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Keywords: if, f(x), g(x), function, divide by, the value, (f/g)(5), 5, 270

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2 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

from the question above,

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1 year ago

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