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2 years ago

What is the magnitude of the electric force between two point charges with Q1 = -1.5 C and Q2 = 0.8 C at a distance of 1 km?

Physics

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

F = -10800 N

Explanation:

Given that,

Charge 1, $q_1=-1.5\ C$

Charge 2, $q_2=0.8\ C$

Distance between the charges, $d=1\ km=10^3\ m$

We need to find the electric force acting between two point charges. Mathematically, it is given by :

$F=k\dfrac{q_1q_2}{d^2}$

$F=-9\times 10^9\times \dfrac{1.5\times 0.8}{(10^3)^2}$

F = -10800 N

So, the magnitude of electric force between two point charges is 10800 N. Hence, this is the required solution.

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A boy in a wheelchair (total mass 54.5 kg) has speed 1.40 m/s at the crest of a slope 2.10 m high and 12.4 m long. At the bottom

babymother [125]

Answer:

630.75 j

Explanation:

from the question we have the following

total mass (m) = 54.5 kg

initial speed (Vi) = 1.4 m/s

final speed (Vf) = 6.6 m/s

frictional force (FF) = 41 N

height of slope (h) = 2.1 m

length of slope (d) = 12.4 m

acceleration due to gravity (g) = 9.8 m/s^2

work done (wd) = ?

we can calculate the work done by the boy in pushing the chair using the law of law of conservation of energy

wd + mgh = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d)

wd = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d) - (mgh)

where wd = work done

m = mass

h = height

g = acceleration due to gravity

FF = frictional force

d = distance

Vf and Vi = final and initial velocity

wd = (0.5 x 54.5 x 6.9^2) - (0.5 x 54.5 x 1.4^2) + (41 x 12.4) - (54.5 X 9.8 X 2.1)

wd = 630.75 j

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2 years ago

What happens if you move a magnet near a could of wire

noname [10]

Answer:

The wire would stick to the magnet????????????????????????

Explanation:

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2 years ago

A soccer player takes a corner kick, lofting a stationary ball 33.0° above the horizon at 15.0 m/s. If the soccer ball has a mas

Alexxandr [17]

Explanation:

It is given that,

Mass of the soccer ball, m = 0.425 kg

Speed of the ball, u = 15 m/s

Angle with horizontal, $\theta=33^{\circ}$

Time for which the player's foot is in contact with it, $\Delta t = 5.1\times 10^{-2}\ s$

Part A,

The x component of the soccer ball's change in momentum is given by :

$\Delta p_x=mv\ cos\theta$

$\Delta p_x=0.425\times 15\ cos(33)$

$p_x=5.34\ kg-m/s$

The y component of the soccer ball's change in momentum is given by :

$\Delta p_y=mv\ sin\theta$

$\Delta p_y=0.425\times 15\ sin(33)$

$p_y=3.47\ kg-m/s$

Hence, this is the required solution.

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2 years ago

A truck loaded with sand accelerates along a highway. The driving force on the truck remains constant. What happens to the accel

pickupchik [31]

Answer:

Acceleration will increase.

Explanation:

The relation between force, mass and acceleration according to the Newton's second law of motion is given as:

F = ma

We are given that the driving force on the truck remains constant, so F is constant here. We can rewrite the above equation as:

$a=\frac{F}{m}$

Since, F is constant, the acceleration of the truck is inversely proportional to the mass.

There is a hole at the bottom of the truck through which the sand is being lost at a constant rate. Since, the sand is being lost, the overall mass of the truck is being reduced.

Since, the acceleration of the truck is inversely proportional to the mass, the reduced mass will result in an increased acceleration.

So, the acceleration of the truck will increase.

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2 years ago

true or false/ force field that exists in the space around every massive body is called electric field

musickatia [10]

Answer:

True

Explanation:

An electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

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