Answer:
![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
![\sqrt[4]{\sqrt[3]{2^2}} =((2^2)^\frac{1}{3})^\frac{1}{4}\\\\=(2^2)^\frac{1}{12}\\\\=2^\frac{2}{12}\\\\=2^\frac{1}{6}\\\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%20%3D%28%282%5E2%29%5E%5Cfrac%7B1%7D%7B3%7D%29%5E%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%3D%282%5E2%29%5E%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B2%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
Answer:
Yes,they are congruent.
Step-by-step explanation:
We are required to make two transformations and prove that they are congruent.
First Transformation:Now rotate the polygon FGHIJ by 90° about the axis parallel to x-axis and passinfg through the vertex I.You can observe that the sides are of same length AB=GF=2 units.
Second Transformation: Keeping the polygon ABCDE constant shift the centre of polygon FGHIJ to the centre of polygon ABCDE you will observe thta they exactly overlap on each other hence they are congruent with each other.
Answer:
6 x 2.5 = 15
8 x 2.5 = 20
L x W = 300 square units
Step-by-step explanation:
Brainliest?
# 12 should be the last one
