3/(x+2) = 2/x
multiply both fractions by x(x+2) to cancel out the bottoms
so it becomes 3x = 2x+4
ow subtract 2X from both sides and you get
x = 4
so it took Juan 4 hours
it took Yumi 2 hours more so 4+2 = 6 hours
They are both right triangles so we can use the Pythagorean
theorem to solve.
6. B = sqrt(15^2-9^2)
B = 12 mm
7. B = sqrt(26^2-10^2)
B = 24 Cm
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:
And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees
Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Answer:
The correct answer is d.
Step-by-step explanation:
Any point that is co planar with one another and is also equidistant from a given point is a circle. We need it to be co planar, otherwise it would be 3-dimensional and create a sphere. And if they we not all equidistant, they would not make an even circle (it'd be an oval or another shape).