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2 years ago

Slow moving vehicles must display ___________ emblem at the rear to warn of their low speed.

Physics

2 answers:

Naddik [55]2 years ago

7 0

Answer:

Reflective emblem

Explanation:

A slow moving vehicle must display a reflective emblem at the rear to warn of their low speed. The sign of emblem is triangular in shape indicating that any sad incident have happened. Slow moving vehicles are generally prone to accident because of low visibility so they must display reflective emblem at rear.

KIM [24]2 years ago

6 0

<span>Slow moving vehicles must display reflective emblem at the rear to warn of their low speed.

The sign consists of a triangle and the primary purpose is to prevent any sad incident to happen, as slow moving vehicle (SMV) can cause serious accidents due to the less visibility at various times, therefore the sign must be visible enough. </span>

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Three ropes A, B and C are tied together in one single knot K.

arsen [322]

The tension in the rope B is determined as 10.9 N.

<h3>Vertical angle of cable B</h3>

tanθ = (6 - 4)/(5 - 0)

tan θ = (2)/(5)

tan θ = 0.4

θ = arc tan(0.4) = 21.8 ⁰

<h3>Angle between B and C</h3>

θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰

Apply cosine rule to determine the tension in rope B;

A² = B² + C² - 2BC(cos A)

B = C

A² = B² + B² - (2B²)(cos A)

A² = 2B² - 2B²(cos 43.6)

A² = 0.55B²

B² = A²/0.55

B² = 65.3/0.55

B² = 118.73

B = √(118.73)

B = 10.9 N

Thus, the tension in the rope B is determined as 10.9 N.

Learn more about tension here: brainly.com/question/24994188

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8 0

1 year ago

Read 2 more answers

An object is dropped from a bridge. A second object is thrown downward 1.48 s later. They both reach the water 48.1 m below at t

pashok25 [27]

To solve this problem we will apply the linear motion kinematic equations. With the data provided we will calculate the time of the first object to fall. Later we will get the time difference between the two. This difference will allow us to find the free fall distance. Through the distance we will find the initial velocity, that is,

$x = v_0 t +\frac{1}{2}at^2$

$48.1 = 0*t + \frac{1}{2} (9.8)t^2$

$t = 3.13s$

The second object is thrown downward at one second later and it meets the first object at the water is

$t' = 3.13 -1.48$

$t' = 1.65s$

The distance of the object will travel due to free fall acceleration is

$x = v_0 t+\frac{1}{2} at^2$

$x = 0*(1.65) +\frac{1}{2}(9.8)(1.65)^2$

$x = 13.34m$

The distance of the object will travel due to its initial velocity is

$v_0 = \frac{d_0}{t}$

$d_0 = v_0 t$

$48.1-13.34 = v_0 (1.65)$

$v_0 = 21.06m/s$

Therefore the initial speed of the second object is 21.06m/s

8 0

3 years ago

Cell phones are technology that is popular throughout the world. Would this technology be of use in rural areas of the world

bonufazy [111]

Unless there is service it wifi, no. To access most features on a cellphone you need wifi or service. These features can include communicating with others or watching a video. Cellphones are practically useless without internet connection.

6 0

2 years ago

Read 2 more answers

Do we know which has more potential energy? object A or B? Best answer with reasoning gets brainliest.

babymother [125]

Answer:

Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

Explanation:

We know the object with the most potential energy and this is the object at C.

Potential energy is the energy due to the position of a body above the ground surface.

The higher a body is above ground, the more its potential energy.

Potential energy = mass x acceleration due to gravity x height

So;

Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

This is because, the height and mass of the objects are not quantified using numbers.

Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.

3 0

2 years ago

The answer please to this and how it’s urgent

oksano4ka [1.4K]

Answer:

rA = 9 i + 9 j

rB = 12 i - 9 j

rB - rA = 3 i - 18 j

so distance in between them

= √[3×3 + 18 × 18 )

= √(9+324)

= √333

= 18.3 m

6 0

2 years ago