There are 13 protons because the atomic number (the number in the top left corner) represents the number of protons. Then, to find the number of neutrons, you take the number of protons and subtract it from the atomic mass (the number on the bottom) when it is rounded. The number of electrons is the same as the protons when the atom is neutral
QUESTION 33
The length of the legs of the right triangle are given as,
6 centimeters and 8 centimeters.
The length of the hypotenuse can be found using the Pythagoras Theorem.
Answer: C
QUESTION 34
The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.
The length of the other leg can be found using the Pythagoras Theorem,
Answer:B
QUESTION 35.
We want to find the distance between,
(2,-1) and (-1,3).
Recall the distance formula,
Substitute the values to get,
Answer: 5 units.
QUESTION 36
We want to find the distance between,
(2,2) and (-3,-3).
We use the distance formula again,
Answer: D
Answer:
Step-by-step explanation:
non linear because linear has always to the first power
What you have to do first is you have 5 owners correct? Well you take anything they're sharing in this case it's delay/debt, so you divide $110 by 5 and you should get $22. This means that each owner would have to pay $22 to the delay.
Answer:
A) see attached for a graph. Range: (-∞, 7]
B) asymptotes: x = 1, y = -2, y = -1
C) (x → -∞, y → -2), (x → ∞, y → -1)
Step-by-step explanation:
<h3>Part A</h3>
A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:
This has a vertical asymptote at x=1, and a hole at x=2.
The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.
The graph is attached.
The range of the function is (-∞, 7].
__
<h3>Part B</h3>
As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.
The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.
__
<h3>Part C</h3>
The end behavior is defined by the horizontal asymptotes:
for x → -∞, y → -2
for x → ∞, y → -1