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2 years ago

Juan read 300 pages in 5 days. Which reading rate is equivalent

Mathematics

1 answer:

Marta_Voda [28]2 years ago

6 0

60 pages in one day 1/60

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Write a model for the statement V varies jointly as h and the fifth power of r. Group of answer choices LaTeX: V=khr^5 V = k h r

hjlf

Answer:

Option A)

$V = khr^5$

Step-by-step explanation:

We are given the following in the question:

V varies jointly as h and the fifth power of r.

$V\propto h\\V\propto r^5$

Combing the two equations, we get,

$V\propto hr^5$

Now, removing the sign of proportionality and adding the constant of proportionality, we get,

$V = khr^5$

where k is the constant of proportionality.

Thus, the correct answer is

Option A)

$V = khr^5$

7 0

2 years ago

A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func

djyliett [7]

Answer:

$y=120 * 1.1^x$ --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

$x \to months$

$y \to mice$

So, we have:

$(x_1,y_1) = (0,120)$ --- Monday

$(x_2,y_2) = (1,132)$ --- One month later

Required

The function

The function is represented as:

$y=ab^x$

In $(x_1,y_1) = (0,120)$ , we have:

$120 = a * b^0$

$120 = a * 1$

$120 = a$

$a=120$

In $(x_2,y_2) = (1,132)$ , we have:

$132 = a * b^1$

$132 = a * b$

Substitute: $a=120$

$132 = 120 * b$

Solve for b

$b = \frac{132}{120}$

$b = 1.1$

So, the function is:

$y=ab^x$

$y=120 * 1.1^x$

To calculate the monthly rate (r), we have:

$y =a(1 + r)^x$

Compare to: $y =ab^x$

$1 + r = b$

Make r the subject

$r = b-1$

Substitute $b = 1.1$

$r = 1.1-1$

$r = 0.1$

Express as percentage

$r = 0.1*100\%$

$r = 10\%$

5 0

2 years ago

What is 1 2/3 - (-5 2/3)

arsen [322]

Answer:

the answer is 7.33

Step-by-step explanation:

I used a calculator

6 0

1 year ago

Read 2 more answers

9) Simplify 2x^5-6^2+4x^4y/2x

KonstantinChe [14]

Answer:

x^4+2x^3y-3x

Step-by-step explanation:

6 0

2 years ago

The temperature at 6.00 am was - 12 the temperature increased by 1/2 each hour for 6 hours what was the temperature in degrees F

Illusion [34]

Answer: -9 degrees Fahrenheit

Step-by-step explanation:

Given: Temperature at 6:00 AM = -12 degrees Fahrenheit

Temperature increased each hour = $\dfrac12$ degrees Fahrenheit

Temperature increase in 6 hours = $6\times\dfrac12=3\text{ degrees Fahrenheit}$

Temperature at noon = Temperature at 6:00 AM+Temperature increase in 6 hours

= -12+3 degrees Fahrenheit

= -9 degrees Fahrenheit

Hence, the temperature in degrees Fahrenheit at noon= -9 degrees Fahrenheit

8 0

2 years ago