2 years ago

-x+3y=10 find x and y intercept

1 answer:

8 0

$-x+3y=10 \\ \\
\hbox{x-intercept: } y=0: \\
-x+3 \times 0=10 \\
-x=10 \\
\boxed{x=-10} \\ \\
\hbox{y-intercept: } x=0: \\
-0+3y=10 \\
3y=10 \\
y=\frac{10}{3} \\
\boxed{y=3 \frac{1}{3}}$

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