Counting atoms in a compound can be done by taking one element at a time and multiplying the subscript of the element and the number of molecules of the compounds. For example, H2O, there are two atoms of H adn 1 atom of oxygen.
Answer:
Explanation:
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In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:
In such a way, we solve for the final volume, V2, to obtain:
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Answer: The name given to is Gallium (III) sulfate.
Explanation: This is an ionic compound because in aqueous solution it dissociates into its respective ions.
Naming of Ionic compounds.
- Name the cation first and then write its oxidation number in roman numerical.
- Then name the anion or polyatomic ions without writing any prefix of the number of atoms present in it.
- The name of the anion should have a suffix '-ide' like for chlorine, the name will be chloride etc..
- For polyatomic ions, the suffix used will be '-ate' like for the name will be sulfate etc..
Name of the given ionic compound is Gallium (III) Sulfate.
because 72:96 is an equivalent of 12:16 and that if you multiply 12 times 6 you get 72 and if you multiply 16 by 6 you get 96
Answer:
Solution's mass = 200.055 g
[PbSO₄] = 275 ppm
Explanation:
Solute mass = 0.055 g of lead(II) sulfate
Solvent mass = 200 g of water
Solution mass = Solvent mass + Solution mass
0.055 g + 200 g = 200.055 g
ppm = μg of solute / g of solution
We convert the mass of solute from g to μg
0.055 g . 1×10⁶ μg/ 1g = 5.5×10⁴μg
5.5×10⁴μg / 200.055 g = 275 ppm
ppm can also be determined as mg of solute / kg of solution
It is important that the relation is 1×10⁻⁶
Let's verify: 0.055 g = 55 mg
200.055 g = 0.200055 kg
55 mg / 0.200055 kg = 275 ppm