The aquarium has 3 more yellow fish than green fish.
60% of the fish are yellow.
To find:
How many green fish are in the aquarium?
Step-by-step explanation:
Let there be x number of fish in the aquarium.
60% of the fish are yellow.
So there are 60x/100 = 3x/5 yellow fish.
Then (100 - 60)% = 40% fish are green.
So there are 40x/100 = 2x/5 green fish.
Given that, there are 3 more yellow fish than green fish
⇒ 3x/5 = 2x/5 + 3
⇒ 3x/5 = (2x + 15)/5
⇒ 3x = 2x + 15
⇒ 3x - 2x = 15
⇒ x = 15
Now, 2x/5 = 2/5 × 15 = 2 × 4 = 6
Answer:
There are 6 green fish in the aquarium.
20x+20y=900
I hope that helps. You'll have to isolate each variable. X= kite, y=website.
Let the supplement be s.
180=s+115 => s=180-115= 65 degrees
Answer:
I don't believe there is a slope or y-intercept for this expression.
Step-by-step explanation:
There is no vertical, horizontal or oblique asymptotes that I have found.
I hope this somewhat helped to answer your question.
They approximately live the same distance away.
