The answer ............................:

Box 1

Alex73 [517]

10g

Explanation:

Box 1, Mass of A = 10g

Box 2, Mass of B = 5g

Box 3, = 1A + 1B

Unknown:

Mass of B that would combine with mass of 20g of A

Solution:

Mass ratio of A to B:

$\frac{mass of A}{mass of B}$ = mass ratio

$\frac{10}{5}$ = mass ratio

The mass ratio of A to B = 2: 1

Now, number of B that will combine with 20g of A;

$\frac{mass of A}{mass of B}$ = mass ratio

$\frac{20}{mass of B}$ = $\frac{2}{1}$

Mass of B = 10g

10g of B would combine with 20g of A

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7 0

2 years ago

Read 2 more answers

Calcuate the number of<br> grams of solute in 453.9mL<br> of 0.237 M calcium acetate

AysviL [449]

The number of grams : 17.082 g

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

453.9 mL of 0.237 M calcium acetate

mol

$\tt mol=M\times V=0.237\times 0.4539=0.108$

mass

MW Ca(C₂H₃OO)₂ : 158,17 g/mol

$\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g$

4 0

2 years ago

The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 2.60 g of naphthalene (C10H8) in 675 g of be

Mrac [35]

<u>Answer:</u> The freezing point of solution is 5.35°C

<u>Explanation:</u>

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 4.90°C/m

$m_{solute}$ = Given mass of solute (naphthalene) = 2.60 g

$M_{solute}$ = Molar mass of solute (naphthalene) = 128.2 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 675 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 4.90^oC/m\times \frac{2.60\times 1000}{128.2g/mol\times 675}\\\\\text{Freezing point of solution}=5.35^oC$

Hence, the freezing point of solution is 5.35°C

3 0

2 years ago

Which of the following statements is true for radioactive reactions:

sasho [114]

Answer:

d) Nucleus of the element does not change during the react

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8 0

1 year ago

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Julissa combined baking soda and calcium chloride solution in a beaker. she observed bubbling and a white solid formed. Julissa

Mamont248 [21]

Answer:

A

Explanation:

With chemical reactions, there are various factors that affect the rate of the reaction. One of these is temperature.

When you raise the temperature, the reaction will move faster. Why? Temperature is directly correlated with the kinetic energy (basically, the energy that makes the particles move). Higher temperatures mean higher kinetic energies. Particles with higher kinetic energies move faster, which makes them more likely to collide. When collisions occur more frequently, the reaction follows through more quickly.

Thus, when Julissa warms the solutions, she will see that bubbling and white solid formation (the products of the reaction) occus faster. So, the answer is A.

Hope this helps!

3 0

2 years ago