Answer:
indeed
Step-by-step explanation:
The perimeter of these can be found by adding length and width and then multiplying by two.
Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.
Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6
And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8
So it would be C.
Answer:
63/9 = 7 -> Yes
-94 -> Yes
30/6 = 5 -> Yes
-16/3 ~ -5,33 -> Nope
-29,86 -> Nope
Step-by-step explanation:
Integers are whole Numbers.
For example 1,2,3,4,5...
The numbers between numbers are rational numbers.
Fir example:
1,2 ( between 1 and 2)
3,8 (between 3 and 4)
2,6 (between 2 and 3)
Find the value of r(q(4)), so first you need to find the value of q(4).
q(4), this means that x = 4, so substitute/plug it into the equation to find the value of q(x) when x = 4:
q(x) = -2x - 1 Plug in 4 into "x" since x = 4
q(4) = -2(4) - 1
q(4) = -8 - 1
q(4) = -9
Now that you know the value of q(4), you can find the value of r(x) when x = q(4)
r(x) = 2x² + 1
r(q(4)) = 2(q(4))² + 1 Plug in -9 into "q(4)" since q(4) = -9
r(q(4)) = 2(-9)² + 1
r(q(4)) = 2(81) + 1
r(q(4)) = 163 163 is the value of r(q(4))
Hello,
you may not used what you are going to prove in a proof (la thèse)