Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:
<u>Area of triangle DAC:</u>
Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>
Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
1/4 = 2/8
7/8 - 1/4 = 7/8 - 2/8 = (7-2)/8 = 5/8
Answer: 5/8
Answer:
3/10
Step-by-step explanation: you multiply 3 and 1/10