The total gallons of sports drink Jaylen made using 9/10 of a large cooler with water and 6 cups of sports drink concentrate is 3.75 gallons
<h3>Total gallons</h3>
- Water in the large cooler = 9/10
Space remaining = 1 - 9/10
= 10-9 / 10
= 1/10
1/10 = 6 cups
- Total gallons of sport drink = x
6 cups / total = 1/10
6 × 10 = total × 1
60 cups = total
Cups to gallons:
16 cups = 1 gallon
Total gallons of sport drink, x = 60 cups / 16
= 3.75 gallons
Complete question:
To make a sports drink for the football team, Jaylen filled 9/10 of a large cooler with water. Then, he filled the remaining space with 6 cups of sports drink concentrate. How many gallons of sports drink did Jaylen make?
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Given that the time taken to get to campus is inversely proportional to driving rate, let the time be t and rate be r, thus the function will be written as:'
t=k/r
where
k is the constant of proportionality given by:
k=tr
when r=20 mph, t=1.25 hrs
thus
k=20×1.25
k=25 miles
thus the formula is:
t=25/r
when r=55 mph, the value of t will be:
t=25/55
t=5/11 hours
b - 10 = 7
Take 10 to the other side.
b = 17
Multiply by 4 to isolate b
b × 4 = 17 × 4
4 and 4 cancels out
b = 68
Yes, 1/3 is greater than 1/4. 1/3= 33.3% and 1/4= 25%