<span>1. (f+g)(x) = f(x) +g(x)
.. = (</span>x^2-36) +(<span>x^3+2x^2-10)
.. = x^3 +3x^2 -46
2. </span>(f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81
<span>3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10</span>
Multiply $20 by 20% good luck
The equations are dependent (they're the same equation).
If you multiply the bottom one by 5, you get the top one.
Answer:
x = 5/-6 + (√13)/-6
x = 5/-6 -(√13)/-6
Step-by-step explanation:
2x^2 = -x^2 - 5x - 1. Subtract 2x^2 from both sides.
-3x^2 - 5x - 1. Do the quadratic formula.
That gives you:
-5/6 ± (√13)/-6.
