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2 years ago

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Question 3(Multiple Choice Worth 4 points) (02.01)Polygon LMNP slides 5 units right and 4 units down on the coordinate plane. If

the original measure of angle M was 50 degrees, what is the measure of angle M'? 40 degrees 45 degrees 50 degrees 130 degrees

2 answers:

lozanna [386]2 years ago

4 0

The answer would be C) 50 degrees.

N76 [4]2 years ago

3 0

Answer:

The answer is 50

Hope this helps

:) Get a good grade

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jamal completed his math homework in 2/3 of an hour and his reading homework in 3/5 of an hour. How much time did it take him to

Assoli18 [71]

Answer:

Step-by-step explanation: We have to add how much time it took him to do all of his homework. To do this, we have to add 2/3 and 3/5.

First, we have to find a LCM between 3 and 5.

The LCM between those numbers are 15.

Next we find out what number to multiply 3 by to get 15, we multiply it by 5.

2 * 5 = 10

3 * 5 = 15

Next we find out what number to multiply 5 by to get 15, we multiply it by 3.

3 * 3 = 9

5 * 3 = 15

10/15+9/15=19/15

We are left off with 1 4/15

So it took him 1 hour and 4/15 minutes to do his homework.

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2 years ago

Please help!<br> This is mathematics!

Elanso [62]

Answer:

30, 30, 32, 32, 34, 38, 38, 38. Thats how you first need to set it up then what you do is add them all up which would equal to 272. Then you take 272 dived by how many numbers there are (theres 8 numbers) so you do 272/8 which would be 34! So 34 would be your answer.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Write (2p)^4 without exponents.

Fed [463]

Answer:

= 8p

Step-by-step explanation:

Steps

2p · 4

Remove parentheses: (a) = a

= 2p · 4

Multiply the numbers: 2 · 4 = 8

= 8p

5 0

2 years ago

First five terms of n2+5

artcher [175]

$a_n=n^2+5\\\\a_1=1^2+5=1+5=6\\\\a_2=2^2+5=4+5=9\\\\a_3=3^2+5=9+5=14\\\\a_4=4^2+5=16+5=21\\\\a_5=5^2+5=25+5=30$

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2 years ago

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Solve the equation in the complex number system. x^2-12x+40=0

mylen [45]

solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Step-by-step explanation:

Solve the equation:

$x^2-12x+40=0$

We can solve using quadratic Formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b = -12, c = 40

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i$

So, solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

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5 0

2 years ago