Determine which of the following equations, when graphed, intersect at the point (4, 0).
1 answer:
Answer:
x - y = 4
x + y = 4
Step-by-step explanation:
Substitute x=4 and y=0 in every equation. If both sides of the equal sign are equal, (LS=RS, left side equals right side) then the graph intersects at (4,0).
- x - y = 4
- (4) - 0 = 4
-4 = 4
LS≠RS
x - y = 4
4 - 0 = 4
4 = 4
LS=RS
2 x + y = 7
2(4) + 0 = 7
8 = 7
LS≠RS
2 x + y = -7
2(4) + 0 = -7
8 = -7
LS≠RS
x + y = 4
4 + 0 = 4
4 = 4
LS=RS
2 x - y = 7
2(4) - 0 = 7
8 - 0 = 7
8 = 7
LS≠RS
Only x - y = 4 and x + y = 4 intersect at (4, 0).
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Answer:
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Step-by-step explanation:
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I think your equation is wrong. the domain of f(x)= 5x+2 is ALL REAL NUMBERS. That means it’s negative infinity to positive infinity.
D. 21cm because you divide all sides by 2 then get your slope form and multiply by seven
The triangles are similar because of the SAS postulate. The sides are proportional and angle T is equal in both.
