Answer:
It is the secon option ∆TRS ≈ ∆TPQ ; SAS
Step-by-step explanation: angle t is equal to angle t because it is the same angle
line TR divided by line TP is equal to line TS divided by TQ
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
a little late
205 1/5 is your answer
Step-by-step explanation:
break down the 3-D figure
Find area of triangle A=1/2bh
=1/2(8 inch)(6 9/10inch)
=1/2(8 inch)(69/10 inch)
=138/5 square inch
then multiply two because you have 2 triangles
=138/5 (2)
= 276/5 square inch
= 55 1/5 sq.in
Find area of rectangle
A = lw
=6 1/4 in (8 in)
= 25/4 (8 in.)
= 50 sq. in.
then multiply by 3 because of the three rectangles
= 50 sq. inch (3)
= 150 sq. in.
Add all together
55 1/5 sq. inch + 150 sq. inch = 205 1/5 sq. inch