<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
7 / 36
Step-by-step explanation:
Using the sample space attached,
Required outcome = multiple of 5 from the sun of two rolled dice = 7
Total possible outcomes =(number of faces)² = 6² = 36
Therefore, the probability of obtaining a sum which is a multiple of 5 is :
P(sum which is a multiple of 5) :
Required outcome / Total possible outcomes
= 7 / 36
When you have lines in graphs for ex
Y=2x+7
2x is the rate of change
7 is the instant amt if the x=0 (or the y-intercept)
Answer:
length : 8 m
width : 13/2 = 6.5 m
Step-by-step explanation:
area of rectangle = l(ength)×w(idth) = 52
l = 2w - 5
=> (2w - 5)×w = 52
=> 2w² -5w - 52 = 0
we know, when transforming this quadratic equation into a multiplication of two expressions of w, that we need to have 2w and w (to make 2w²), and then which 2 numbers multiply to 52 and add to -5 (when one is multiplied by 2 due to 2w) : -13 and 4
=> (2w - 13)×(w + 4) = 0
=> 2 solutions for w :
2w-13 = 0
2w = 13, w = 13/2
w+4 = 0, w = -4
negative values for a side length of a shape do not make sense, so the only usable solution is w = 13/2
=> l = 2w - 5 = 13 - 5 = 8