(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
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(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
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-11x^2-5x-3
-(-11x^2-33x-33)
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28x+30
So our remainder will be 28x+30
Step-by-step explanation:
Wendy
-20 = x/2 + 7
-20 -7 = x/2 + 7 -7
-27 = x/2
-54 = x
x = -54
because it's math rule
Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2
Answer:
I believe the answer would be 21.
Step-by-step explanation:
the shadow of the tall flag is three times the small flag, so the height of the flag should also be three times the height. which is 21
Y = ax + b;
0.89 = a * 2 + b and 2.09 = a * 5 + b =>
=> 2.09 - 0.89 = a * 5 + a * 2 + b - b => 1.20 = 3 * a => a = 1.20 / 3 => a = 0.40;
b = 0.89 - 0.40 * 2 => b = 0.89 - 0.80 => b = 0.09;
y = 0.40x + 0.09 => 0.40x - y + 0.09 = 0 is the linear equation.
