(6+18)^2 = m^2 + m^2
=> 2m^2 = (24)^2
=> m = 24/sqrt(2)
For this case we have the following equation:
y = 150 * (1.06) ^ t
For the first month we have:
y = 150 * (1.06) ^ 1
y = 159 $
For the second month we have:
y = 150 * (1.06) ^ 2
y = 168.54 $
For the third month we have:
y = 150 * (1.06) ^ 1
y = 178.65 $
Answer:
d. $ 159.00 + $ 168.54 + $ 178.65
Answer:
I don't know this at all I'm sorry, but ur down bad yo
Step-by-step explanation:
By evaluating the <em>linear</em> function f(x) = x - 3 at x = 5 and discarding the another function in the table given, we conclude that f(5) = 2 belongs to that <em>linear</em> equation.
<h3>What function contains a given relationship?</h3>
In this problem we must check if the given relationship between the <em>independent</em> variable (x) and the <em>dependent</em> variable (y) exists in any of the two functions: (i) a table, (ii) an expression.
After a quick analysis, we conclude that f(5) = 2 is a point of the linear function f(x) = x - 3. Here is the proof:
f(5) = 5 - 3
f(5) = 2
To learn more on linear equations: brainly.com/question/11897796
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15*5=75
79-75=4
If Luis gives each of his classmates 5 pencils each, he will have 4 leftover to give to his teacher
16*4=64
79-64=15
If Luis gives himself AND each of his classmates 4 pencils each, he will have 15 leftover to give to his teacher
So... If Luis decides to take an equal share of pencils along with his classmates, his teacher will receive more pencils.