10,000 units of momentum.
p=mv
20,000=m(2v)
10,000=mv
Answer:
330.24 Hz
Explanation:
Given:
Frequency, f = 320 Hz
L1 = 25.8 cm
L2 = 78.4 cm
L3 = 131.1 cm
Let the wavelength be λ
Then, L1 which is the length of the column of air is λ/4.
λ/4 = 25.8 cm
λ = 25.8 × 4 = 103.2 cm = 1.032 m
Then, speed of sound in air is:
v = λ f
⇒ v = 1.032 × 320 Hz
⇒ v = 330.24 m/s
Answer
given,
mass of the rod = 1.50 Kg
length of rod = 0.85 m
rotational velocity = 5060 rev/min
now calculating the rotational inertia of the system.
where L is the length of road, we will take whole length of rod because mass is at the end of it.
I = 1.084 kg.m²
hence, the rotational inertia the system is equal to I = 1.084 kg.m²
Using Newton's second law of motion:
F=ma ; [ F = force (N: kgm/s^2);m= mass (kg); a = acceleration (m/s^2)
Given: Find: Formula: Solve for m:
F: 2500N mass:? F=ma Eq.1 m=F/a Eq. 2
a= 200m/s^2
Solution:
Using Eq.2
m= (2500 kgm/s^2)/ (200m/s^2) = 12.5 kg
Answer: Rough endoplasmic reticulum, cytoplasm, inside mitochondria
Explanation: