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2 years ago

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.

Mathematics

2 answers:

tresset_1 [31]2 years ago

5 0

Answer:

b = 101.52

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac CosB

b^2 = 105^2 + 9^2 - 2(105)(9) Cos 65°

b^2 = 11 106 - 798.75

b^2 = 10 307.25

b = 101.52

garik1379 [7]2 years ago

3 0

Answer:101.52

Step-by-step explanation:

Given

a=105

c=9

$B=65^{\circ}$

using cosine rule

$2acCosB=a^2+c^2-b^2$

$2(105)(9)Cos65=105^2+9^2-b^2$

$b^2=11025+81-798.7485$

b=101.524

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Answer:

Step-by-step explanation:

To find the coordinate of the midpoint of segment QB, first, find the distance from Q to B.

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2 years ago

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.​

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.