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2 years ago

Which chemical reaction absorbs energy?

Physics

2 answers:

andre [41]2 years ago

8 0

Photosynthesis. Photosynthesis is the process the plant uses to absorbs light to make food

nalin [4]2 years ago

5 0

Photosythesis it a process of a plant take that energy and producing foods while the rest are push energy away as a destructive force current

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PLEASE HELP SOLVE THIS PHOTO BELOW

polet [3.4K]

Answer:

Explanation:

The pattern is adding .5 to the cm every .1 in weight you just continue the table

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2 years ago

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A car is traveling in a straight line at a constant speed. The car's engine is exerting a constant force on the car. Explain why

kherson [118]

Answer:

because its not going down a long hill instead its going on a leveled street

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2 years ago

A student runs 35 m east, then 12 m west. What is the distance run by the student?

lora16 [44]

47m total just add them up 35 + 12 = 47

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2 years ago

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I need both parts please (a) Given a material with an attenuation coefficient (a) of 0.6/cm, what is the intensity of a beam (wi

Masteriza [31]

Answer:

After it has traveled through 1 cm : $I(1 \ cm) = 0.5488 I_0$

After it has traveled through 2 cm : $I(2 \ cm) = 0.3012 I_0$

After it has traveled through 1 cm : $od( 1\ cm) = 0.2606$

After it has traveled through 2 cm : $od( 2\ cm) = 0.5211$

Explanation:

For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient $\mu$ the formula is:

$I(x) = I_0 e^{-\mu x}$

where I is the intensity of the beam, $I_0$ is the incident intensity and x is the length of the material traveled.

For our problem, after travelling 1 cm:

$I(1 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 1 cm}$

$I(1 \ cm) = I_0 e^{- 0.6}$

$I(1 \ cm) = 0.5488 \ I_0$

After travelling 2 cm:

$I(2 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 2 cm}$

$I(2 \ cm) = I_0 e^{- 1.2}$

$I(2 \ cm) = 0.3012 \ I_0$

The optical density od is given by:

$od(x) = - log_{10} ( \frac{I(x)}{I_0} )$ .

So, after travelling 1 cm:

$od( 1\ cm) = - log_{10} ( \frac{0.5488 \ I_0}{I_0} )$

$od( 1\ cm) = - log_{10} ( 0.5488 )$

$od( 1\ cm) = - ( - 0.2606)$

$od( 1\ cm) = 0.2606$

After travelling 2 cm:

$od( 2\ cm) = - log_{10} ( \frac{0.3012 \ I_0}{I_0} )$

$od( 2\ cm) = - log_{10} ( 0.3012 )$

$od( 2\ cm) = - ( - 0.5211)$

$od( 2\ cm) = 0.5211$

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2 years ago

What is the momentum of a 3kg ball that is traveling at 5m/s

marta [7]

Answer:

15 Kg m/s

Explanation:

momentum p = mv

p is momentum

m is mass (kg)

v is velocity (m/s)

p = (3) (5m/s)

p= 15 Kg m/s

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