The current flowing in each resistor of the circuit is 4 A.
<h3>
Equivalent resistance of the series resistors</h3>
The equivalent resistance of the series circuit is calculated as follows;
6 Ω and 4 Ω are in series = 10 Ω
5 Ω and 10Ω are in series = 15 Ω
<h3>Effective resistance of the circuit</h3>
<h3>Current flowing in the circuit</h3>
V = IR
I = V/R
I = 24/6
I = 4 A
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The three resistors are connected to the same points of the circuit, so they are in parallel configuration. The equivalent resistance of 3 resistors in parallel is given by:
If we plug the values of the resistances into the formula, we find
From which we find the equivalent resistance:
So, the correct answer is B.
Object 2 has more kinetic energy
Explanation:
The kinetic energy of an object is the energy possessed by the object due to its motion, and it is given by
where
m is the mass of the object
v is its speed
In this problem, for object 1:
m = 2 kg
v = 2 m/s
So its kinetic energy is
For object 2,
m = 4 kg
v = 3 m/s
So its kinetic energy is
Therefore, object 2 has more kinetic energy.
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Answer:
2
Explanation:
We know that in the Fraunhofer single-slit pattern,
maxima is given by
Given values
θ=2.12°
slit width a= 0.110 mm.
wavelength λ= 582 nm
Now plugging values to calculate N we get
Solving the above equation we get
we N= 2.313≅ 2