The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
In polar form:
r = √(x² + y²) and cosФ = x / √(x² + y²)
Hence:
r(1 - 2cosФ) = 1
√(x² + y²) [1 - 2(x / √(x² + y²))] = 1
√(x² + y²) - 2x = 1
Take square of both sides:
x² + y² - 4x√(x² + y²) + 4x² = 1
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
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Answer:
(b/2)^2
Step-by-step explanation:
Answer:
x = 3
Step-by-step explanation:
Let's solve your equation step-by-step.
5x + 11 = -3x +35
Add 3x to both sides.
5x + 11 + 3x = -3x + 35 + 3x
8x + 11 = 35
Subtract 11 from both sides.
8x + 11 - 11 = 35 - 11
8x = 24
Divide both sides by 8.
x = 3
So therefore, that is how you found your answer: x = 3
Answer:
First you need to get your variable(x) by itself.
You do that by adding 16 to both sides of the greater than sign.
The 16 cancels or goes away. and 16 + 4 =20.
Your new equation is 20<4x
Finally you divide 20 by 4 to get 5
Your answer is 5<x or x>5.