Mike had 5 5/6 he gave 11/6 to mathew and 4/6 to nolan and 3/4 to sanjar how much does mike have now

2 answers:

4 0

To find out, first you got to convert 11/6 into a mixed fraction. You do it by dividing 11 ÷ 6 which is 1 5/6. Now you have to do 5 5/6 - 1 5/6 which is 4. We now have to do 4 - 4/6 which is 3 1/3. 3 1/3 - 3/4 is 2 7/12. Your answer is 2 7/12

dexar [7]2 years ago

3 0

Find a common denominator or the bottom number of a fraction. 5 and 5/6 - 11/6 - 4/6 - 3/4 = 140/24 - 44/24 - 16/24 - 18/24 = 96/24 - 16/24 - 18/24=62/24 or 2 and 7/12.

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A sample of 30 distance scores measured in yards has a mean of 7, a variance of 16, and a standard deviation of 4. You want to c

Nikolay [14]

Answer:

21, 144, 12

Step-by-step explanation:

Given that a sample of 30 distance scores measured in yards has a mean of 7, a variance of 16, and a standard deviation of 4.

Let X be the distance in yard.

i.e. each entry of x is multiplied by 3.

New mean variance std devition would be

E(3x) = $3E(x) = 21$

Var (3x) = $3^2 Var(x) = 9(16) =144$

Std dev (3x) = $\sqrt{144 } =12$

Thus we find mean and std devition get multiplied by 3, variance is multiplied by 9

4 0

2 years ago

70 pointsss for the correct answer

nignag [31]

Answer:

f(x) = 12x³ - 19x² + 17x - 17

Step-by-step explanation:

We can the numerator by multiplying the denominator by the quotient, and then adding the remainder.

We're given a denominator of 4x - 5

a quotient of 3x² - x + 3

and a remainder of -2

so the original numerator is:

(4x - 5)(3x² - x + 3) - 2

= 12x³ - 4x² + 12x - 15x² + 5x - 15 - 2

= 12x³ - 19x² + 17x - 17

Let's test that by dividing it by 4x -5 with long division:

$\ \ \ \ \ \ \ \ \ \ 3x^2 - x + 3\\4x - 5\overline{)12x^3 - 19x^2 + 17x - 17}\\.\ \ \ \ \ \ \ \ \ \underline{2x^3 - 15x^2}\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ -4x^2 + 17x\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{-4x^2 + 5x} \\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 12x - 17\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{12x - 15}\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2R$