The value of the derivative at the maximum or minimum for a continuous function must be zero.
<h3>What happens with the derivative at the maximum of minimum?</h3>
So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.
Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).
If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.
So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.
If you want to learn more about maximums and minimums, you can read:
brainly.com/question/24701109
Step-by-step explanation:
Solution,
since two of these triangle are similar so,
i) LK/LJ=MN/NO
or,j/8=18/12
or,j=18×8/12
.°. j = 12m
ii)JK/JL=MO/NO
or,10/8=n/12
or,120/8=n
.°.n=15m
Answer: X = t or minus 4 square root 3 and X= 4 square root 3 Explanation: add 48 on both sides bring down x squared = 48 take the square root on both sides you get X= t or - 4 square root 3 and X=4 square root 3) Animex yw
3/4 I believe since 6 1/4- 51/2 is 3/4
Answer: 71.6°
tan-1(9/3) = 71.56505118°
