Given: Initial velocity of toy car (u ) = 0
Final velocity of toy car (v) = 0.12 m/s
Required time (t) = 0.1 s
To find: The acceleration of the toy car.
Let the acceleration of the toy car be (a)
Formula Used: 1st kinematic equation of motion
v = u + at ---------------------------(i)
Here, all alphabets are in their usual meanings
Now, from equation (i), we shall calculate the value of 'a'.
so, a = (v - u) /t
or, a = (0.12 m/s - 0) / 0.1s
or, a = 1.2 m/s²
Hence, the required acceleration of the toy car will be 1.2 m/s².
Answer:
x = 727.5 km
Explanation:
With the conditions given using trigonometry, we can find the tangent
tan θ = CO / CA
With CO the opposite leg and CE is the adjacent leg which is the distance from the Tierral to Sun
D =150 10⁶ km (1000m / 1 km)
D = 150 10⁹ m.
We must take the given angle to radians.
1º = 3600 arc s
π rad = 180º
θ = 1 arc s (1º / 3600 s arc) (pi rad / 180º) =
θ = 4.85 10⁻⁶ rad
That angle is extremely small, so we can approximate the tangent to the angle
θ = x / D
x = θ D
x = 4.85 10-6 150 109
x = 727.5 103 m
x = 727.5 km
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