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2 years ago

MA = 8x – 2, mB = 2x – 8, and mC = 94 – 4x. List the sides of ABC in order from shortest to longest.

Mathematics

1 answer:

LUCKY_DIMON [66]2 years ago

3 0

I hope this helps you

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Question 5 - a , b , c , d ??

wel

A) 110/21 = 5 5/21
B) 10
C) 21/4 = 5 1/4
D) 16/5 = 3 1/5

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2 years ago

Which rational number is one tick mark to the left of -3/4

Zolol [24]

I'm assuming each tickmark is 1/4 = 0.25

If that assumption is correct, then going one tickmark to the left of -3/4 lands you on -4/4 which simplifies to -1.

So -1 is one tickmark to the left of -3/4

Again, this all hinges on the assumption that each tickmark is 1/4 a unit away from its neighbor.

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2 years ago

Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni

dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

$(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})$

It is provided that, Renee recognizes that 7 and $\frac{1}{7}$ are reciprocals, so she would like to find their product before she multiplies by $\frac{13}{29}$ .

The associative property of multiplication states that:

$a\times b\times c=(a\times b)\times c=a\times (b\times c)$

The commutative property of multiplication states that:

$a\times b\times c=a\times c\times b=c\times a\times b$

The distributive property of multiplication states that:

$a\cdot (b+c)=a\cdot b+a\cdot c$

The identity property of multiplication states that:

$a\times 1=a\\b\times 1=b$

So, Renee should use the commutative property of multiplication to find the product of 7 and $\frac{1}{7}$ ,

$(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}$

Thus, the correct option is commutative property.

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2 years ago

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(7.58•105)+(2.871•106)

Svet_ta [14]

1,100.226 is your answer :)

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2 years ago

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Find the value of x

kodGreya [7K]

Answer:

Last Option

Step-by-step explanation:

We have a triangle and we know its three sides.

We want to find one of your anguos. Then we use the cosine theorem.

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx$

Where

$c = 14\\a = 11\\b = 19$

Now we solve for x from the equation

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx\\\\\\14^2 = 11^2 + 19^2 -2(11)(19)cosx\\\\14^2 -11^2 -19^2 = 2(11)(19)cosx\\\\-286=2(11)(19)cosx\\\\cosx = \frac{-286}{2(11)(19)}\\\\x = arcos(\frac{-286}{2(11)(19)})\\\\x = 46.8\°$

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2 years ago

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