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2 years ago

9

MATH NEEED HELP PLEASE

1 answer:

serg [7]2 years ago

3 0

I can try to help out, The Distance between A and H is 12 feet same with H and B So My answer for a. The Lighthouse is 24 Feet tall, And for b. if you look at K and G's Distance from the Lighthouse Its the same distance in which kelly is looking at the lighthouse, which is 26 Ft. for C. Has me abit puzzled, Math Necessarily isn't my Strong suit so hopefully someone will answer C for you

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What is the value of x?

Phantasy [73]

Answer:

value of x = 5.8 mm

Step-by-step explanation:

We have given,

Two right triangles EDH and EDG.

In right triangle EDH, EH = 56mm , DH = 35 mm

Using Pythagoras theorem we can find ED.

i.e EH² = ED²+DH²

56²=ED²+35²

ED²=56²-35²

ED = √(56²-35²) = 7√39 = 43.71 mm

Now, Consider right triangle EDG

Here, EG=44.8mm , GD = x+4 and ED = 7√39

Again using Pythagoras theorem,

EG² = ED² + DG²

44.8²= (7√39)²+ (x+4)²

(x+4)² = 44.8² - (7√39)²

x+4 = √(44.8² - (7√39)²)

x+4 = 9.8

or x = 9.8 - 4 = 5.8 mm

Hence we got the value of x = 5.8 mm

6 0

2 years ago

- 2.2f + 0.55 f– 15 - 8=

Andrews [41]

Https://photomath.net/s/rRVj6K

7 0

2 years ago

Please help and thank you

tresset_1 [31]

Answer:

A. The description represents an arithmetic sequence because the successive y-values have a common difference of 600

Step-by-step explanation:

The equation that this situation is describing would be

$y=600x+20000$

This would mean that this equation would be an arithmetic series

5 0

2 years ago

In triangle abc, cos A= -0.6. Find A and Tan A

Tresset [83]

Answer:

Part 1) $A=126.87^o$

Part 2) $tan(A)=-\frac{4}{3}$

Step-by-step explanation:

we have

$cos(A)=-0.6$

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

$cos(A)=-0.6$

using a calculator

$A=cos^{-1}(-0.6)=126.87^o$

step 2

Find the sin(A)

we know that

$sin^2(A)+cos^2(A)=1$

substitute the value of cos(A)

$sin^2(A)+(-0.6)^2=1$

$sin^2(A)=1-0.36$

$sin^2(A)=0.64$

$sin(A)=0.8$

step 3

Find tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{0.8}{-0.6}$

Simplify

$tan(A)=-\frac{4}{3}$

5 0

2 years ago

Which is the best estimate for (6.3x10^-2)(9.9x10^-3) written in scientific notation?

ozzi

It should be 6.237*10^-4

8 0

2 years ago

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