Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Answer:
X=11 not so sure about y
Step-by-step explanation:
Since this is a square, x and 11 sides are the same. So, x would have to be 11. Sorry I can’t help on y but I hope this helps.
Recall, The arc length [s] of a section of a circle is equal to the circles radius [r] times the central angle [theta] that the arc subtends. in radians.
r = 2.5 m.
s = 3 m.
LOLLLLLL that’s crazy but okah doe ;)