The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
Answer:
x=2
Step-by-step explanation:
After solving with substitution, you would know x = 2
You are given
a distance of 20 kilometers and time of 30 minutes. You are required to find
for the speed of the travelling object. The equation for speed is distance over
time. Speed is a scalar quantity. It tells you the direction of the travelling object.
The solution in this problem is,
Speed =
distance/time
Speed = 20
kilometers / 30 minutes
<u>Speed =
2/3 kilometers per minute or 0.667 kilometers per minute</u>
<span>Therefore,
the speed of the object is 0.667 km per minute.</span>