All categories

2 years ago

Joey organised a large wedding

2 answers:

7 0

Ok so we need to find out what fraction of 12 the veggies are. To do this we need to add the beef and chicken so
1/3 x 4 = 4/12 so we have a common denominator to add both fractions.
4/12 + 5/12 = 9/12
This means that 3/12 chose veggie
3/12 is equivalent to 1/4 (divide by three)
so if we multiple 69 by 4 we get the total number of guests.
69 x 4 = 276
I hope this helps

VikaD [51]2 years ago

5 0

Answer:

can you tell me more details?

Step-by-step explanation:

You might be interested in

The equation h(t) = -16t^2? + 32t + 128 models the path of a ball thrown in the air from the top of a building. After how many s

Lelu [443]

Answer:

1 second

Step-by-step explanation:

4 0

2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

2 years ago

Is it scaling isosceles or equilateral and what is the answer

garik1379 [7]

Answer:

$scalene$