Volume of sphere: 
, put $r=5 in$
Volume of cylinder:$ \pi r^2 h$, put $r=8 in, \: h=11 in$
Answer:
The chance of an average six-sided number cube landing one one number is 1/6, or approximately 16.67%. When rolling a number cube 100 times, the average number of times it lands on any specific number should be fairly close to 16.67.
A 6 being rolled 42 times and 33 times means that it is <em>very likely</em> not to be a standard number cube. Although we cannot know for certain, the chance of this happening is very low.
The answer is x^4-6x^3+12x^2-28/x^2
Answer:
Subtract
1
1
1
from both sides of the equation
2
+
1
=
1
1
2
+
1
−
1
=
1
1
−
1
2
Simplify
3
Divide both sides of the equation by the same term
4
Simplify
Solution
=
5
Step-by-step explanation:
Answer:
Step-by-step explanation: you just need to find the greatest factors and least multiple then do it to two numbers
