Here when an object is placed on the level floor then in that case there are two forces on the object
1). Weight of object downwards (mg)
2). Normal force due to floor which will counterbalance the weight (N)
so when no force is applied on the box at that time normal force is counter balanced by weight.
Now here it is given that A person tried to lift the box upwards
So now there are two forces on the box
1). Applied force of person
2). Normal force due to ground
So now these two forces will counter balance the weight of the crate
So we can write an equation for force balance like
given that
here
m = 30 kg and
g = acceleration due to gravity = 10 m/s^2
now from above equation
So force applied by the person must be 150 N
Answer:
4.1666666 seconds
Explanation:
100 divided by 24 will give you about 4.1666666 seconds or 4 1/6 seconds. Hope it helps!
E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶ kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J
Complete Question: A +10 nC charge is located at the origin. What is the electric field at the position (x2,y2)= (-5.0cm, 0cm)? Write electric field vector in component form.
E2x, E2y=? N/C
Answer:
Ex = -3.6*10⁴ N/C Ey=0
Explanation:
As the charge producing the field is positive, the direction of the field, which is the one that would take a positive test charge located in the point of interest, will be away from this point, pointing to the left.
If we choose the positive direction to be to the right, the electric field component along the x-axis will be negative.
The magnitude of the field can be obtained applying the electric field definition, and the Coulomb's Law to the charge in the origin, as follows:
E = k*q/r² = 9*10⁹N*m²/C²*10⁻⁸C/(0.05)² m² = 3.6*10⁴ N/C
As the electric field follows the same line as the electric force, it has only component on the x axis, so:
Ex = -3.6*10⁴ N/C
Ey = 0
