For
|a|=b, solve for
a=b and a=-b
so
|a-4|=3a-6
solve
a-4=3a-6 and a-4=-(3a-6)
first one
a-4=3a-6
minus a from both sides
-4=2a-6
add 6 to both sides
2=2a
divide by 2
1=a
other
a-4=-(3a-6)
a-4=-3a+6
add 3a both sides
4a-4=6
add 4 to both sides
4a=10
divide by 4
a=10/4
a=5/2
a=5/2 and 1
F(x) = -(x2+x-72)
y = -(x - 8)(x + 9)
the solutions are x = 8, -9; so the parabola is upside down (umbrella) crossing the x at 8 and -9, meaning that -9 + 8 = -1/2 = -0.5 is where the focus is, or x = -0.5 as the axis of symmetry
Answer:
Step-by-step explanation:
Sum of cubes is a^3+b^3=(a+b)(a^2-ab+b^2)
64x^3+1
(4x+1)(16x^2-4x+1)